Drużkowski's reduction to cubic-linear maps
JC in every dimension ⇔ JC for x + (Ax)^{*3}, in every dimension
Drużkowski refined the cubic normal form further: after adding variables, each nonlinear component can be taken to be the cube of a linear form. The Keller condition then says that the matrix is nilpotent, and the problem becomes one about matrices.[1] The proof starts from the Bass–Connell–Wright and Yagzhev cubic-homogeneous form. In 2001 Drużkowski showed one may also assume . Like its parent, the reduction raises the dimension, so it bears on the all-dimensions conjecture only, not on any fixed dimension.
In 2005 Drużkowski proved that cubic-linear maps with symmetric Jacobian and constant nonzero determinant are tame automorphisms. So a counterexample can be put in cubic-linear form or in the symmetric form of de Bondt and van den Essen, but never in both at once.[2]
Jointly with the 2026 counterexample, the reduction guarantees a non-invertible cubic-linear Keller map in some dimension. None has been exhibited explicitly in the sources the research found.
- ↑ L. M. Drużkowski, An effective approach to Keller's Jacobian Conjecture, Math. Ann. 264 (1983) 303–313, doi:10.1007/BF01459126.
- ↑ L. M. Drużkowski, The Jacobian Conjecture: symmetric reduction and solution in the symmetric cubic linear case, Ann. Polon. Math. 87 (2005) 83–92.
Relations
- uses The cubic reduction of Bass–Connell–Wright and Yagzhev proved · V3
The Keller condition then says that the matrix is nilpotent, and the problem becomes one about matrices. The proof starts from the Bass–Connell–Wright and Yagzhev cubic-homogeneous form. [1]
- related to The Jacobian conjecture in dimension n refuted · V0
Like its parent, the reduction raises the dimension, so it bears on the all-dimensions conjecture only, not on any fixed dimension.
- related to The symmetric reduction proved · V3
So a counterexample can be put in cubic-linear form or in the symmetric form of de Bondt and van den Essen, but never in both at once. [2]
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